det (T) = 5.
For detailed explanation of the method (see adjacent Fig A2):
Draw a slant line through the entries in the upper left and lower right. Form the product of these entries (8). Draw a slant line through the entries in the upper right and lower left. Form the product of these entries (3). From
From the first product subtract the second product: 8 - 3 = 5.
Also in Fig 2 is the general formula ad − bc for finding the determinant value of any 2x2 matrix.
A common notation for a determinant introduced here. It avoids using the name of the matrix and replaces the large parentheses ( ) by vertical lines | |.
det(U) = -42
Copy columns 1 and 2 to the right of the determinant..
Draw a slant line (main diagonal) from the entry in the upper left (position [1,1]) down through the entry in the center of the determinant (position [2,2]) and down to the entry in the lower right (position[3,3]). Draw another slant line (main diagonal) from the top middle entry (position [1,2] parallel to the first slant line through two m9ore entries. Draw a third slant line from the top right entry parallel to the other two slant lines.
Matrices A and B are stored as
[M "A", 2,3, 5,1,9, 3,2,11], [M "B", 2,3, 4,-1,3, 2,6,-4]
Consider the following sets of linear equations in two unknowns:
(*) 5x + y = 9 5u + v = 9 5α + β = 9 A 3x + 2y = 11 3u + 2v = 11 3α + 2β = 11Matrix A in Fig 1 contains the same numerical information from each set of equations. Each set is easily solved. Multiply the top equation by 2 and subtract the bottom equation from the result.
x = 1 u = 1 α = 1 y = 4 v = 4 β = 4These solution-equations may be written as:
(**) x + 0y = 1 u + 0v = 1 α + 0β = 1 0x + y = 4 0u + v = 4 0α + β = 4The matrix W contains the numerical data from these equations.
The purpose of this discussion is to proceed from equations (*) to equations (**) using only matrices. However, the longer equations with letters will be written for comparison.
Since the matrices do not include x,y,+,= there is much less writing them. However, zeros are needed when a variable letter is absent from the cofrresponding equation. Also it is possible to have a computer do the matrix method of solving the equations. However, there are "better" methods to be discussed later.
The following linear equations show how to get values for x' and y' from values given to x and y:
(*) x' = x + 2y y' = 3x - yThe following equations show how to get values for x" and y" from values given to x' and y':
(**) x" = 4x' +3y' y" = 2x' - 4y'Then values given to x and y eventually cause values to be given to x" and y". For example, if 1 and 3 are assigned to x and y respectively in equations (*) then x' and y' receive values 7 and 0. But if these values are given to x' and y' in equations (**) then x' and y" receive values 28 and 14. Derive the equaations that assign values to x" and y" directly from x and y.
The idea is simple: replace x' and y' in equations (**) by their equals in equations (*):
x" = 4(x + 2y) + 3(3x-y) y" = 2(x + 2y) - 4(3x-y)These equations simplify to:
(***) x" = 13x + 5y y" = -10x + 8yIf 1 and 3 are assigned again to x and y but this time in equations (***) then x" and y" again receive the values 28 and 14.
The coefficient matrices for equations (**) and (*) are below and the computer gives their product on the right side of the equal sign. Notice that this product is equal to the coefficient matrix for equations (***). Click here to see more on the motivation of the rule for multiplying matrices.